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  • 5
    \$\begingroup\$ c = ~~a-~~b should be c = ~~a+~~b. Also, you can implicitly cast to integer using |0, for example Math.random()*6|0. \$\endgroup\$
    – mellamokb
    Commented Jun 1, 2011 at 19:48
  • 7
    \$\begingroup\$ It's cheaper to coerce a string to a number with the unary plus operator. If a and b are strings, you can do +a+b to convert to number and add them. \$\endgroup\$
    – Peter Olson
    Commented Dec 2, 2011 at 21:38
  • 11
    \$\begingroup\$ I swear I'm going to use d- -b in my code someday... \$\endgroup\$
    – John Dvorak
    Commented Dec 19, 2013 at 14:21
  • 5
    \$\begingroup\$ +a+b doesn't work (at least on mine...) // a="1",b="1",+a+b // gives "11" \$\endgroup\$
    – imma
    Commented Jan 16, 2014 at 11:46
  • 3
    \$\begingroup\$ For "Use Array-Access for repeat function calls" if you're using the function more than twice on the same object, what's a bit shorter is to assign the function to a new member like a.f=a.longfunctionname;a.f(b);a.f(c);a.f(d) \$\endgroup\$
    – Martin Ender
    Commented Sep 11, 2014 at 14:40