Revisions to How do I conditionally add attributes to React components?

Add curly braces to avoid confusing newcomers.

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edited May 22, 2022 at 13:59

juandemarco's answer is usually correct, but here is another option.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition) {
  inputProps.disabled = true;
}

Render with spread, optionally passing other props also.

<input
    value="this is overridden by inputProps"
    {...inputProps}
    onChange={overridesInputProps}
 />

juandemarco's answer is usually correct, but here is another option.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition)
  inputProps.disabled = true;

Render with spread, optionally passing other props also.

<input
    value="this is overridden by inputProps"
    {...inputProps}
    onChange={overridesInputProps}
 />

juandemarco's answer is usually correct, but here is another option.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition) {
  inputProps.disabled = true;
}

Render with spread, optionally passing other props also.

<input
    value="this is overridden by inputProps"
    {...inputProps}
    onChange={overridesInputProps}
 />

Used a more direct cross reference. Removed some meta information (this belongs in comments).

Source Link

edited Jan 29, 2020 at 1:03

Just throwing another option out there, but @juandemarco's answerjuandemarco's answer is usually correct, but here is another option.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition)
  inputProps.disabled = true;

Render with spread, optionally passing other props also.

<input 
    value="this is overridden by inputProps" 
    {...inputProps} 
    onChange={overridesInputProps}
 />

Just throwing another option out there, but @juandemarco's answer is usually correct.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition) inputProps.disabled = true;

Render with spread, optionally passing other props also.

<input 
    value="this is overridden by inputProps" 
    {...inputProps} 
    onChange={overridesInputProps}
 />

juandemarco's answer is usually correct, but here is another option.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition)
  inputProps.disabled = true;

Render with spread, optionally passing other props also.

<input
    value="this is overridden by inputProps"
    {...inputProps}
    onChange={overridesInputProps}
 />

added 5 characters in body

Source Link

edited Jan 16, 2016 at 20:41

Just throwing another option out there, but @juandemarco's answer is usually correct.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition) propsinputProps.disabled = true;

Render with spread, optionally passing other props also.

<input 
    value="this is overridden by inputProps" 
    {...inputProps} 
    onChange={overridesInputProps}
 />

Just throwing another option out there, but @juandemarco's answer is usually correct.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition) props.disabled = true;

Render with spread, optionally passing other props also.

<input 
    value="this is overridden by inputProps" 
    {...inputProps} 
    onChange={overridesInputProps}
 />

Just throwing another option out there, but @juandemarco's answer is usually correct.

Build an object how you like:

var inputProps = {
  value: 'foo',
  onChange: this.handleChange
};

if (condition) inputProps.disabled = true;

Render with spread, optionally passing other props also.

<input 
    value="this is overridden by inputProps" 
    {...inputProps} 
    onChange={overridesInputProps}
 />

Source Link

created Jul 1, 2015 at 14:34

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