1998 Florida Attorney General election
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  Butterworth: 50–60% 60–70% 70–80% 80–90% >90% Bludworth: 50–60% 60–70% 70–80% 80–90% >90% Tie: 40–50% 50% No votes | |||||||||||||||||
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| Elections in Florida |
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 Government |
The 1998 Florida Attorney General election was held on November 3, 1998. Democratic incumbent Bob Butterworth defeated Republican nominee David H. Bludworth with 59.56% of the vote. As of 2024, this was the last time a Democrat was elected Florida Attorney General.
Primary elections
[edit]Primary elections were held on September 1, 1998.[1]
Democratic primary
[edit]Candidates
[edit]- Bob Butterworth, Florida Attorney General
- Ellis Rubin, attorney
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Bob Butterworth | 475,757 | 81.80 | |
| Democratic | Ellis Rubin | 105,865 | 18.20 | |
| Total votes | 581,622 | 100.00 | ||
Republican primary
[edit]
Bludworth
- 50–60%
- 60–70%
- 70–80%
Dudley
- 50–60%
- 60–70%
- 70–80%
Candidates
[edit]- David H. Bludworth
- Fred Dudley, State Senator
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | David H. Bludworth | 298,375 | 53.89 | |
| Republican | Fred Dudley | 255,274 | 46.11 | |
| Total votes | 553,649 | 100.00 | ||
General election
[edit]Candidates
[edit]- Bob Butterworth, Democratic
- David H. Bludworth, Republican
Results
[edit]| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | Bob Butterworth | 2,301,328 | 59.56% | ||
| Republican | David H. Bludworth | 1,562,269 | 40.44% | ||
| Majority | 739,059 | ||||
| Turnout | |||||
| Democratic hold | Swing | ||||
References
[edit]- ^ a b c "September 1, 1998 Primary Election". Secretary of State of Florida. 1998. Retrieved June 1, 2021.
- ^ "November 3, 1998 General Election". Secretary of State of Florida. 1998. Retrieved June 1, 2021.